Y=4-0,5x^2

Solution for Y=4-0,5x^2 equation:

=4-0.5Y^2

We move all terms to the left:

-(4-0.5Y^2)=0

We get rid of parentheses

0.5Y^2-4=0

a = 0.5; b = 0; c = -4;
Δ = b2-4ac
Δ = 02-4·0.5·(-4)
Δ = 8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{8}=\sqrt{4*2}=\sqrt{4}*\sqrt{2}=2\sqrt{2}$
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{2}}{2*0.5}=\frac{0-2\sqrt{2}}{1}
=-\frac{2\sqrt{2}}{1}
$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{2}}{2*0.5}=\frac{0+2\sqrt{2}}{1}
=\frac{2\sqrt{2}}{1}
$